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2(2+4)=3/4(24-8r)
We move all terms to the left:
2(2+4)-(3/4(24-8r))=0
Domain of the equation: 4(24-8r))!=0We add all the numbers together, and all the variables
r∈R
-(3/4(-8r+24))+26=0
We multiply all the terms by the denominator
-(3+26*4(-8r+24))=0
We calculate terms in parentheses: -(3+26*4(-8r+24)), so:
3+26*4(-8r+24)
determiningTheFunctionDomain 26*4(-8r+24)+3
Wy multiply elements
104r(-+3
We use the square of the difference formula
104r(-3
Back to the equation:
-(104r(-3)
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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We calculate terms in parentheses: -(104r(-3), so:
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| 9x+6=6x+30 | | 7(1-6x)+3=220 | | x+6(x-3)=4(x-3) | | 2/4i=5 | | 7x+12=2(x+) | | 2(2h−1)=3(2h+2) | | 11=7x5-4x | | x^2-10x+38=3x-2 | | b2−5=25 | | b/2−5=25 | | 22/16=d/32 | | 93=6(x+5)+3x | | -(5x-11)-x=6-6x | | -12s—-s+-2s=-13 | | -3(6-2n)=n-28 | | 5g+49g-10=0 | | 14q-12q+2q=16 | | 35+6x=-7(8x-5) | | 19m+m-16m+4m+m=9 | | -3x-3(7x+26)=-198 | | w=1/3=-2/5 | | 12(7c-5)=9c-7 | | 16+20p=18p | | 3x+6=54.X= | | -2q-17-16q=-20q+13 | | 5x+15+8x+5=124 | | 7-m=9 | | -12r-18=-8r+10 | | 5x+15-8x+5=124 | | 3x+-2(1-x)=1 | | 5/3x4+4=2/3x4 | | 3+c+9c=9c-4 |