2(2+m)+4(4+2)=108

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Solution for 2(2+m)+4(4+2)=108 equation: 



2(2+m)+4(4+2)=108

We move all terms to the left:

2(2+m)+4(4+2)-(108)=0

determiningTheFunctionDomain
2(2+m)-108+4(4+2)=0

We add all the numbers together, and all the variables

2(m+2)-108+46=0

We add all the numbers together, and all the variables

2(m+2)-62=0

We multiply parentheses

2m+4-62=0

We add all the numbers together, and all the variables

2m-58=0

We move all terms containing m to the left, all other terms to the right

2m=58

m=58/2

m=29

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