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2(2+x)-(6-7x)=13x-(1+5x)
We move all terms to the left:
2(2+x)-(6-7x)-(13x-(1+5x))=0
We add all the numbers together, and all the variables
2(x+2)-(-7x+6)-(13x-(5x+1))=0
We multiply parentheses
2x-(-7x+6)-(13x-(5x+1))+4=0
We get rid of parentheses
2x+7x-(13x-(5x+1))-6+4=0
We calculate terms in parentheses: -(13x-(5x+1)), so:We add all the numbers together, and all the variables
13x-(5x+1)
We get rid of parentheses
13x-5x-1
We add all the numbers together, and all the variables
8x-1
Back to the equation:
-(8x-1)
9x-(8x-1)-2=0
We get rid of parentheses
9x-8x+1-2=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1
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