2(2+y)-y=4+2(y+1)

Solution for 2(2+y)-y=4+2(y+1) equation:

2(2+y)-y=4+2(y+1)

We move all terms to the left:

2(2+y)-y-(4+2(y+1))=0

We add all the numbers together, and all the variables

2(y+2)-y-(4+2(y+1))=0

We add all the numbers together, and all the variables

-1y+2(y+2)-(4+2(y+1))=0

We multiply parentheses

-1y+2y-(4+2(y+1))+4=0


We calculate terms in parentheses: -(4+2(y+1)), so:

4+2(y+1)

determiningTheFunctionDomain
2(y+1)+4

We multiply parentheses

2y+2+4

We add all the numbers together, and all the variables

2y+6

Back to the equation:

-(2y+6)


We add all the numbers together, and all the variables

y-(2y+6)+4=0

We get rid of parentheses

y-2y-6+4=0

We add all the numbers together, and all the variables

-1y-2=0

We move all terms containing y to the left, all other terms to the right

-y=2

y=2/-1

y=-2