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2(2-3a)=-3(1+2a)
We move all terms to the left:
2(2-3a)-(-3(1+2a))=0
We add all the numbers together, and all the variables
2(-3a+2)-(-3(2a+1))=0
We multiply parentheses
-6a-(-3(2a+1))+4=0
We calculate terms in parentheses: -(-3(2a+1)), so:We get rid of parentheses
-3(2a+1)
We multiply parentheses
-6a-3
Back to the equation:
-(-6a-3)
-6a+6a+3+4=0
We add all the numbers together, and all the variables
7!=0
There is no solution for this equation
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