2(2-3r)=-5(r-3)=

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Solution for 2(2-3r)=-5(r-3)= equation:



2(2-3r)=-5(r-3)=
We move all terms to the left:
2(2-3r)-(-5(r-3))=0
We add all the numbers together, and all the variables
2(-3r+2)-(-5(r-3))=0
We multiply parentheses
-6r-(-5(r-3))+4=0
We calculate terms in parentheses: -(-5(r-3)), so:
-5(r-3)
We multiply parentheses
-5r+15
Back to the equation:
-(-5r+15)
We get rid of parentheses
-6r+5r-15+4=0
We add all the numbers together, and all the variables
-1r-11=0
We move all terms containing r to the left, all other terms to the right
-r=11
r=11/-1
r=-11

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