2(2-3x)+3(2-2x)=6(2x-3)-3(12x+3)

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Solution for 2(2-3x)+3(2-2x)=6(2x-3)-3(12x+3) equation:



2(2-3x)+3(2-2x)=6(2x-3)-3(12x+3)
We move all terms to the left:
2(2-3x)+3(2-2x)-(6(2x-3)-3(12x+3))=0
We add all the numbers together, and all the variables
2(-3x+2)+3(-2x+2)-(6(2x-3)-3(12x+3))=0
We multiply parentheses
-6x-6x-(6(2x-3)-3(12x+3))+4+6=0
We calculate terms in parentheses: -(6(2x-3)-3(12x+3)), so:
6(2x-3)-3(12x+3)
We multiply parentheses
12x-36x-18-9
We add all the numbers together, and all the variables
-24x-27
Back to the equation:
-(-24x-27)
We add all the numbers together, and all the variables
-12x-(-24x-27)+10=0
We get rid of parentheses
-12x+24x+27+10=0
We add all the numbers together, and all the variables
12x+37=0
We move all terms containing x to the left, all other terms to the right
12x=-37
x=-37/12
x=-3+1/12

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