2(2-3x)-29=8x-(x-23)

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Solution for 2(2-3x)-29=8x-(x-23) equation: 



2(2-3x)-29=8x-(x-23)

We move all terms to the left:

2(2-3x)-29-(8x-(x-23))=0

We add all the numbers together, and all the variables

2(-3x+2)-(8x-(x-23))-29=0

We multiply parentheses

-6x-(8x-(x-23))+4-29=0



We calculate terms in parentheses: -(8x-(x-23)), so:

8x-(x-23)

We get rid of parentheses

8x-x+23

We add all the numbers together, and all the variables

7x+23

Back to the equation:

-(7x+23)



We add all the numbers together, and all the variables

-6x-(7x+23)-25=0

We get rid of parentheses

-6x-7x-23-25=0

We add all the numbers together, and all the variables

-13x-48=0

We move all terms containing x to the left, all other terms to the right

-13x=48

x=48/-13

x=-3+9/13

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