2(2-3x)=3(4x+1)

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Solution for 2(2-3x)=3(4x+1) equation: 



2(2-3x)=3(4x+1)

We move all terms to the left:

2(2-3x)-(3(4x+1))=0

We add all the numbers together, and all the variables

2(-3x+2)-(3(4x+1))=0

We multiply parentheses

-6x-(3(4x+1))+4=0



We calculate terms in parentheses: -(3(4x+1)), so:

3(4x+1)

We multiply parentheses

12x+3

Back to the equation:

-(12x+3)



We get rid of parentheses

-6x-12x-3+4=0

We add all the numbers together, and all the variables

-18x+1=0

We move all terms containing x to the left, all other terms to the right

-18x=-1

x=-1/-18

x=1/18

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