2(2-3x)=3(x-2)-2-3x

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Solution for 2(2-3x)=3(x-2)-2-3x equation: 



2(2-3x)=3(x-2)-2-3x

We move all terms to the left:

2(2-3x)-(3(x-2)-2-3x)=0

We add all the numbers together, and all the variables

2(-3x+2)-(3(x-2)-2-3x)=0

We multiply parentheses

-6x-(3(x-2)-2-3x)+4=0



We calculate terms in parentheses: -(3(x-2)-2-3x), so:

3(x-2)-2-3x

determiningTheFunctionDomain
3(x-2)-3x-2

We add all the numbers together, and all the variables

-3x+3(x-2)-2

We multiply parentheses

-3x+3x-6-2

We add all the numbers together, and all the variables

-8

Back to the equation:

-(-8)



We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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