2(2-3x)=4(1-3/2x)

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Solution for 2(2-3x)=4(1-3/2x) equation: 


x in (-oo:+oo)

2*(2-(3*x)) = 4*(1-((3/2)*x)) // - 4*(1-((3/2)*x))

2*(2-(3*x))-(4*(1-((3/2)*x))) = 0

2*(2-3*x)-4*((-3/2)*x+1) = 0

2*(2-3*x)-4*(1-3/2*x) = 0

2*(2-3*x)-4*(1-3/2*x) = 0

0 = 0

0 = 0

x belongs to the empty set

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