2(2-q)-(-3)(q-4)=-(3q-4)

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Solution for 2(2-q)-(-3)(q-4)=-(3q-4) equation: 



2(2-q)-(-3)(q-4)=-(3q-4)

We move all terms to the left:

2(2-q)-(-3)(q-4)-(-(3q-4))=0

We add all the numbers together, and all the variables

2(-1q+2)-(-3)(q-4)-(-(3q-4))=0

We multiply parentheses

-2q-(-3)(q-4)-(-(3q-4))+4=0

We multiply parentheses ..

-2q-(-3q+12)-(-(3q-4))+4=0



We calculate terms in parentheses: -(-(3q-4)), so:

-(3q-4)

We get rid of parentheses

-3q+4

Back to the equation:

-(-3q+4)



We get rid of parentheses

-2q+3q+3q-12-4+4=0

We add all the numbers together, and all the variables

4q-12=0

We move all terms containing q to the left, all other terms to the right

4q=12

q=12/4

q=3

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