2(2/5x+8)=4(14-1/5x)

Solution for 2(2/5x+8)=4(14-1/5x) equation:

2(2/5x+8)=4(14-1/5x)

We move all terms to the left:

2(2/5x+8)-(4(14-1/5x))=0


Domain of the equation: 5x+8)!=0

x∈R



Domain of the equation: 5x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2(2/5x+8)-(4(-1/5x+14))=0

We multiply parentheses

4x-(4(-1/5x+14))+16=0

We multiply all the terms by the denominator


4x*5x+16*5x-1+14))-(4(+14))=0

We add all the numbers together, and all the variables

4x*5x+16*5x-1+14))-(414)=0

We add all the numbers together, and all the variables

4x*5x+16*5x=0

Wy multiply elements

20x^2+80x=0

a = 20; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·20·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*20}=\frac{-160}{40}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*20}=\frac{0}{40}
=0
$