2(20+10x)-20+4x=5(20+0,8x)

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Solution for 2(20+10x)-20+4x=5(20+0,8x) equation:



2(20+10x)-20+4x=5(20+0.8x)
We move all terms to the left:
2(20+10x)-20+4x-(5(20+0.8x))=0
We add all the numbers together, and all the variables
2(10x+20)+4x-(5(0.8x+20))-20=0
We add all the numbers together, and all the variables
4x+2(10x+20)-(5(0.8x+20))-20=0
We multiply parentheses
4x+20x-(5(0.8x+20))+40-20=0
We calculate terms in parentheses: -(5(0.8x+20)), so:
5(0.8x+20)
We multiply parentheses
0x+100
We add all the numbers together, and all the variables
x+100
Back to the equation:
-(x+100)
We add all the numbers together, and all the variables
24x-(x+100)+20=0
We get rid of parentheses
24x-x-100+20=0
We add all the numbers together, and all the variables
23x-80=0
We move all terms containing x to the left, all other terms to the right
23x=80
x=80/23
x=3+11/23

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