2(23-2x)=64-10x

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Solution for 2(23-2x)=64-10x equation: 



2(23-2x)=64-10x

We move all terms to the left:

2(23-2x)-(64-10x)=0

We add all the numbers together, and all the variables

2(-2x+23)-(-10x+64)=0

We multiply parentheses

-4x-(-10x+64)+46=0

We get rid of parentheses

-4x+10x-64+46=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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