2(27-b)=100-4b+7(3-b)

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Solution for 2(27-b)=100-4b+7(3-b) equation: 



2(27-b)=100-4b+7(3-b)

We move all terms to the left:

2(27-b)-(100-4b+7(3-b))=0

We add all the numbers together, and all the variables

2(-1b+27)-(100-4b+7(-1b+3))=0

We multiply parentheses

-2b-(100-4b+7(-1b+3))+54=0



We calculate terms in parentheses: -(100-4b+7(-1b+3)), so:

100-4b+7(-1b+3)

determiningTheFunctionDomain
-4b+7(-1b+3)+100

We multiply parentheses

-4b-7b+21+100

We add all the numbers together, and all the variables

-11b+121

Back to the equation:

-(-11b+121)



We get rid of parentheses

-2b+11b-121+54=0

We add all the numbers together, and all the variables

9b-67=0

We move all terms containing b to the left, all other terms to the right

9b=67

b=67/9

b=7+4/9

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