2(29-2x)=3(3x+2)

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Solution for 2(29-2x)=3(3x+2) equation: 



2(29-2x)=3(3x+2)

We move all terms to the left:

2(29-2x)-(3(3x+2))=0

We add all the numbers together, and all the variables

2(-2x+29)-(3(3x+2))=0

We multiply parentheses

-4x-(3(3x+2))+58=0



We calculate terms in parentheses: -(3(3x+2)), so:

3(3x+2)

We multiply parentheses

9x+6

Back to the equation:

-(9x+6)



We get rid of parentheses

-4x-9x-6+58=0

We add all the numbers together, and all the variables

-13x+52=0

We move all terms containing x to the left, all other terms to the right

-13x=-52

x=-52/-13

x=+4

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