2(2C)+3C=28

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Solution for 2(2C)+3C=28 equation: 


Simplifying
2(2C) + 3C = 28

Remove parenthesis around (2C)
2 * 2C + 3C = 28

Multiply 2 * 2
4C + 3C = 28

Combine like terms: 4C + 3C = 7C
7C = 28

Solving
7C = 28

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Divide each side by '7'.
C = 4

Simplifying
C = 4

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