2(2a+2ab+2bc)=4a+4b+4c

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Solution for 2(2a+2ab+2bc)=4a+4b+4c equation:


Simplifying
2(2a + 2ab + 2bc) = 4a + 4b + 4c
(2a * 2 + 2ab * 2 + 2bc * 2) = 4a + 4b + 4c
(4a + 4ab + 4bc) = 4a + 4b + 4c

Add '-4a' to each side of the equation.
4a + 4ab + -4a + 4bc = 4a + 4b + -4a + 4c

Reorder the terms:
4a + -4a + 4ab + 4bc = 4a + 4b + -4a + 4c

Combine like terms: 4a + -4a = 0
0 + 4ab + 4bc = 4a + 4b + -4a + 4c
4ab + 4bc = 4a + 4b + -4a + 4c

Reorder the terms:
4ab + 4bc = 4a + -4a + 4b + 4c

Combine like terms: 4a + -4a = 0
4ab + 4bc = 0 + 4b + 4c
4ab + 4bc = 4b + 4c

Solving
4ab + 4bc = 4b + 4c

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4bc' to each side of the equation.
4ab + 4bc + -4bc = 4b + -4bc + 4c

Combine like terms: 4bc + -4bc = 0
4ab + 0 = 4b + -4bc + 4c
4ab = 4b + -4bc + 4c

Divide each side by '4b'.
a = 1 + -1c + b-1c

Simplifying
a = 1 + -1c + b-1c

Reorder the terms:
a = 1 + b-1c + -1c

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