2(2a-5)=3(a-1)-4

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Solution for 2(2a-5)=3(a-1)-4 equation: 



2(2a-5)=3(a-1)-4

We move all terms to the left:

2(2a-5)-(3(a-1)-4)=0

We multiply parentheses

4a-(3(a-1)-4)-10=0



We calculate terms in parentheses: -(3(a-1)-4), so:

3(a-1)-4

We multiply parentheses

3a-3-4

We add all the numbers together, and all the variables

3a-7

Back to the equation:

-(3a-7)



We get rid of parentheses

4a-3a+7-10=0

We add all the numbers together, and all the variables

a-3=0

We move all terms containing a to the left, all other terms to the right

a=3

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