2(2b+1)=9(3b-6)

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Solution for 2(2b+1)=9(3b-6) equation: 



2(2b+1)=9(3b-6)

We move all terms to the left:

2(2b+1)-(9(3b-6))=0

We multiply parentheses

4b-(9(3b-6))+2=0



We calculate terms in parentheses: -(9(3b-6)), so:

9(3b-6)

We multiply parentheses

27b-54

Back to the equation:

-(27b-54)



We get rid of parentheses

4b-27b+54+2=0

We add all the numbers together, and all the variables

-23b+56=0

We move all terms containing b to the left, all other terms to the right

-23b=-56

b=-56/-23

b=2+10/23

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