2(2b+2)=6(2+2b)

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Solution for 2(2b+2)=6(2+2b) equation: 



2(2b+2)=6(2+2b)

We move all terms to the left:

2(2b+2)-(6(2+2b))=0

We add all the numbers together, and all the variables

2(2b+2)-(6(2b+2))=0

We multiply parentheses

4b-(6(2b+2))+4=0



We calculate terms in parentheses: -(6(2b+2)), so:

6(2b+2)

We multiply parentheses

12b+12

Back to the equation:

-(12b+12)



We get rid of parentheses

4b-12b-12+4=0

We add all the numbers together, and all the variables

-8b-8=0

We move all terms containing b to the left, all other terms to the right

-8b=8

b=8/-8

b=-1

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