2(2b+6)+3(2b-4)=10

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Solution for 2(2b+6)+3(2b-4)=10 equation:



2(2b+6)+3(2b-4)=10
We move all terms to the left:
2(2b+6)+3(2b-4)-(10)=0
We multiply parentheses
4b+6b+12-12-10=0
We add all the numbers together, and all the variables
10b-10=0
We move all terms containing b to the left, all other terms to the right
10b=10
b=10/10
b=1

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