2(2b-2)=-2(b+5)

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Solution for 2(2b-2)=-2(b+5) equation: 



2(2b-2)=-2(b+5)

We move all terms to the left:

2(2b-2)-(-2(b+5))=0

We multiply parentheses

4b-(-2(b+5))-4=0



We calculate terms in parentheses: -(-2(b+5)), so:

-2(b+5)

We multiply parentheses

-2b-10

Back to the equation:

-(-2b-10)



We get rid of parentheses

4b+2b+10-4=0

We add all the numbers together, and all the variables

6b+6=0

We move all terms containing b to the left, all other terms to the right

6b=-6

b=-6/6

b=-1

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