2(2b-7)=1-(3+2b)

Solution for 2(2b-7)=1-(3+2b) equation:

2(2b-7)=1-(3+2b)

We move all terms to the left:

2(2b-7)-(1-(3+2b))=0

We add all the numbers together, and all the variables

2(2b-7)-(1-(2b+3))=0

We multiply parentheses

4b-(1-(2b+3))-14=0


We calculate terms in parentheses: -(1-(2b+3)), so:

1-(2b+3)

determiningTheFunctionDomain
-(2b+3)+1

We get rid of parentheses

-2b-3+1

We add all the numbers together, and all the variables

-2b-2

Back to the equation:

-(-2b-2)


We get rid of parentheses

4b+2b+2-14=0

We add all the numbers together, and all the variables

6b-12=0

We move all terms containing b to the left, all other terms to the right

6b=12

b=12/6

b=2