2(2c+1)-3(3c-4)=40

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Solution for 2(2c+1)-3(3c-4)=40 equation: 


Simplifying
2(2c + 1) + -3(3c + -4) = 40

Reorder the terms:
2(1 + 2c) + -3(3c + -4) = 40
(1 * 2 + 2c * 2) + -3(3c + -4) = 40
(2 + 4c) + -3(3c + -4) = 40

Reorder the terms:
2 + 4c + -3(-4 + 3c) = 40
2 + 4c + (-4 * -3 + 3c * -3) = 40
2 + 4c + (12 + -9c) = 40

Reorder the terms:
2 + 12 + 4c + -9c = 40

Combine like terms: 2 + 12 = 14
14 + 4c + -9c = 40

Combine like terms: 4c + -9c = -5c
14 + -5c = 40

Solving
14 + -5c = 40

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + -5c = 40 + -14

Combine like terms: 14 + -14 = 0
0 + -5c = 40 + -14
-5c = 40 + -14

Combine like terms: 40 + -14 = 26
-5c = 26

Divide each side by '-5'.
c = -5.2

Simplifying
c = -5.2

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