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2(2c+1)c=-13
We move all terms to the left:
2(2c+1)c-(-13)=0
We add all the numbers together, and all the variables
2(2c+1)c+13=0
We multiply parentheses
4c^2+2c+13=0
a = 4; b = 2; c = +13;
Δ = b2-4ac
Δ = 22-4·4·13
Δ = -204
Delta is less than zero, so there is no solution for the equation
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