2(2c+2)=8-4c

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Solution for 2(2c+2)=8-4c equation: 



2(2c+2)=8-4c

We move all terms to the left:

2(2c+2)-(8-4c)=0

We add all the numbers together, and all the variables

2(2c+2)-(-4c+8)=0

We multiply parentheses

4c-(-4c+8)+4=0

We get rid of parentheses

4c+4c-8+4=0

We add all the numbers together, and all the variables

8c-4=0

We move all terms containing c to the left, all other terms to the right

8c=4

c=4/8

c=1/2

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