2(2c+3)+5(c+4)=4(2c+5)+9

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Solution for 2(2c+3)+5(c+4)=4(2c+5)+9 equation: 



2(2c+3)+5(c+4)=4(2c+5)+9

We move all terms to the left:

2(2c+3)+5(c+4)-(4(2c+5)+9)=0

We multiply parentheses

4c+5c-(4(2c+5)+9)+6+20=0



We calculate terms in parentheses: -(4(2c+5)+9), so:

4(2c+5)+9

We multiply parentheses

8c+20+9

We add all the numbers together, and all the variables

8c+29

Back to the equation:

-(8c+29)



We add all the numbers together, and all the variables

9c-(8c+29)+26=0

We get rid of parentheses

9c-8c-29+26=0

We add all the numbers together, and all the variables

c-3=0

We move all terms containing c to the left, all other terms to the right

c=3

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