2(2c+3)=3c+12

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Solution for 2(2c+3)=3c+12 equation:


Simplifying
2(2c + 3) = 3c + 12

Reorder the terms:
2(3 + 2c) = 3c + 12
(3 * 2 + 2c * 2) = 3c + 12
(6 + 4c) = 3c + 12

Reorder the terms:
6 + 4c = 12 + 3c

Solving
6 + 4c = 12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
6 + 4c + -3c = 12 + 3c + -3c

Combine like terms: 4c + -3c = 1c
6 + 1c = 12 + 3c + -3c

Combine like terms: 3c + -3c = 0
6 + 1c = 12 + 0
6 + 1c = 12

Add '-6' to each side of the equation.
6 + -6 + 1c = 12 + -6

Combine like terms: 6 + -6 = 0
0 + 1c = 12 + -6
1c = 12 + -6

Combine like terms: 12 + -6 = 6
1c = 6

Divide each side by '1'.
c = 6

Simplifying
c = 6

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