2(2c-4)=3(c+1)=

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Solution for 2(2c-4)=3(c+1)= equation: 



2(2c-4)=3(c+1)=

We move all terms to the left:

2(2c-4)-(3(c+1))=0

We multiply parentheses

4c-(3(c+1))-8=0



We calculate terms in parentheses: -(3(c+1)), so:

3(c+1)

We multiply parentheses

3c+3

Back to the equation:

-(3c+3)



We get rid of parentheses

4c-3c-3-8=0

We add all the numbers together, and all the variables

c-11=0

We move all terms containing c to the left, all other terms to the right

c=11

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