2(2d-1)-2d=4(d-2)+5

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Solution for 2(2d-1)-2d=4(d-2)+5 equation: 



2(2d-1)-2d=4(d-2)+5

We move all terms to the left:

2(2d-1)-2d-(4(d-2)+5)=0

We add all the numbers together, and all the variables

-2d+2(2d-1)-(4(d-2)+5)=0

We multiply parentheses

-2d+4d-(4(d-2)+5)-2=0



We calculate terms in parentheses: -(4(d-2)+5), so:

4(d-2)+5

We multiply parentheses

4d-8+5

We add all the numbers together, and all the variables

4d-3

Back to the equation:

-(4d-3)



We add all the numbers together, and all the variables

2d-(4d-3)-2=0

We get rid of parentheses

2d-4d+3-2=0

We add all the numbers together, and all the variables

-2d+1=0

We move all terms containing d to the left, all other terms to the right

-2d=-1

d=-1/-2

d=1/2

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