2(2f+4)=4(f+2)

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Solution for 2(2f+4)=4(f+2) equation:


Simplifying
2(2f + 4) = 4(f + 2)

Reorder the terms:
2(4 + 2f) = 4(f + 2)
(4 * 2 + 2f * 2) = 4(f + 2)
(8 + 4f) = 4(f + 2)

Reorder the terms:
8 + 4f = 4(2 + f)
8 + 4f = (2 * 4 + f * 4)
8 + 4f = (8 + 4f)

Add '-8' to each side of the equation.
8 + -8 + 4f = 8 + -8 + 4f

Combine like terms: 8 + -8 = 0
0 + 4f = 8 + -8 + 4f
4f = 8 + -8 + 4f

Combine like terms: 8 + -8 = 0
4f = 0 + 4f
4f = 4f

Add '-4f' to each side of the equation.
4f + -4f = 4f + -4f

Combine like terms: 4f + -4f = 0
0 = 4f + -4f

Combine like terms: 4f + -4f = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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