2(2h-4)=3(h+1)-5

Solution for 2(2h-4)=3(h+1)-5 equation:

2(2h-4)=3(h+1)-5

We move all terms to the left:

2(2h-4)-(3(h+1)-5)=0

We multiply parentheses

4h-(3(h+1)-5)-8=0


We calculate terms in parentheses: -(3(h+1)-5), so:

3(h+1)-5

We multiply parentheses

3h+3-5

We add all the numbers together, and all the variables

3h-2

Back to the equation:

-(3h-2)


We get rid of parentheses

4h-3h+2-8=0

We add all the numbers together, and all the variables

h-6=0

We move all terms containing h to the left, all other terms to the right

h=6