2(2i-6)=28

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Solution for 2(2i-6)=28 equation: 



2(2i-6)=28

We move all terms to the left:

2(2i-6)-(28)=0

We multiply parentheses

4i-12-28=0

We add all the numbers together, and all the variables

4i-40=0

We move all terms containing i to the left, all other terms to the right

4i=40

i=40/4

i=10

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