2(2k+3)=22

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Solution for 2(2k+3)=22 equation: 



2(2k+3)=22

We move all terms to the left:

2(2k+3)-(22)=0

We multiply parentheses

4k+6-22=0

We add all the numbers together, and all the variables

4k-16=0

We move all terms containing k to the left, all other terms to the right

4k=16

k=16/4

k=4

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