2(2k+3)=3(k+6)

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Solution for 2(2k+3)=3(k+6) equation: 



2(2k+3)=3(k+6)

We move all terms to the left:

2(2k+3)-(3(k+6))=0

We multiply parentheses

4k-(3(k+6))+6=0



We calculate terms in parentheses: -(3(k+6)), so:

3(k+6)

We multiply parentheses

3k+18

Back to the equation:

-(3k+18)



We get rid of parentheses

4k-3k-18+6=0

We add all the numbers together, and all the variables

k-12=0

We move all terms containing k to the left, all other terms to the right

k=12

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