2(2k+3)=3(k-4)

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Solution for 2(2k+3)=3(k-4) equation:


2(2k+3)=3(k-4)

We simplify the equation to the form, which is simple to understand 
2(2k+3)=3(k-4)

Reorder the terms in parentheses
+(+4k+6)=3*(k-4)

Remove unnecessary parentheses
+4k+6=+3+*(+k-4+)

Reorder the terms in parentheses
+4k+6=+(+3k-12)

Remove unnecessary parentheses
+4k+6=+3k-12

We move all terms containing k to the left and all other terms to the right. 
+4k-3k=-12-6

We simplify left and right side of the equation. 
+1k=-18

We divide both sides of the equation by 1 to get k. 
k=-18

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