2(2k+4)=3/4(24-8k)

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Solution for 2(2k+4)=3/4(24-8k) equation: 



2(2k+4)=3/4(24-8k)

We move all terms to the left:

2(2k+4)-(3/4(24-8k))=0



Domain of the equation: 4(24-8k))!=0

k∈R



We add all the numbers together, and all the variables

2(2k+4)-(3/4(-8k+24))=0

We multiply parentheses

4k-(3/4(-8k+24))+8=0

We multiply all the terms by the denominator


4k*4(-8k+24))-(3+8*4(-8k+24))=0

Wy multiply elements

16k^2(-+32k(-=0

We use the square of the difference formula

16k^2(-32k(-=0

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