2(2k+8)=3(k-7)

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Solution for 2(2k+8)=3(k-7) equation: 



2(2k+8)=3(k-7)

We move all terms to the left:

2(2k+8)-(3(k-7))=0

We multiply parentheses

4k-(3(k-7))+16=0



We calculate terms in parentheses: -(3(k-7)), so:

3(k-7)

We multiply parentheses

3k-21

Back to the equation:

-(3k-21)



We get rid of parentheses

4k-3k+21+16=0

We add all the numbers together, and all the variables

k+37=0

We move all terms containing k to the left, all other terms to the right

k=-37

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