2(2k-1)=2+3d-1/2

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Solution for 2(2k-1)=2+3d-1/2 equation: 


x in (-oo:+oo)

2*(2*k-1) = 3*d-(1/2)+2 // - 3*d-(1/2)+2

2*(2*k-1)-(3*d)+1/2-2 = 0

2*(2*k-1)-3*d+1/2-2 = 0

(2^2*(2*k-1))/2+(-3*2*d)/2+1/2+(-2*2)/2 = 0

2^2*(2*k-1)-3*2*d-2*2+1 = 0

8*k-6*d-4-4+1 = 0

8*k-6*d-4-3 = 0

8*k-6*d-7 = 0

(8*k-6*d-7)/2 = 0

(8*k-6*d-7)/2 = 0 // * 2

8*k-6*d-7 = 0

x belongs to the empty set

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