2(2k-1)=4(k-2)=

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Solution for 2(2k-1)=4(k-2)= equation:



2(2k-1)=4(k-2)=
We move all terms to the left:
2(2k-1)-(4(k-2))=0
We multiply parentheses
4k-(4(k-2))-2=0
We calculate terms in parentheses: -(4(k-2)), so:
4(k-2)
We multiply parentheses
4k-8
Back to the equation:
-(4k-8)
We get rid of parentheses
4k-4k+8-2=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation

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