2(2k-1)=4(k-2)=

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Solution for 2(2k-1)=4(k-2)= equation: 



2(2k-1)=4(k-2)=

We move all terms to the left:

2(2k-1)-(4(k-2))=0

We multiply parentheses

4k-(4(k-2))-2=0



We calculate terms in parentheses: -(4(k-2)), so:

4(k-2)

We multiply parentheses

4k-8

Back to the equation:

-(4k-8)



We get rid of parentheses

4k-4k+8-2=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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