2(2k-2)=4(k-2)

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Solution for 2(2k-2)=4(k-2) equation: 


Simplifying
2(2k + -2) = 4(k + -2)

Reorder the terms:
2(-2 + 2k) = 4(k + -2)
(-2 * 2 + 2k * 2) = 4(k + -2)
(-4 + 4k) = 4(k + -2)

Reorder the terms:
-4 + 4k = 4(-2 + k)
-4 + 4k = (-2 * 4 + k * 4)
-4 + 4k = (-8 + 4k)

Add '-4k' to each side of the equation.
-4 + 4k + -4k = -8 + 4k + -4k

Combine like terms: 4k + -4k = 0
-4 + 0 = -8 + 4k + -4k
-4 = -8 + 4k + -4k

Combine like terms: 4k + -4k = 0
-4 = -8 + 0
-4 = -8

Solving
-4 = -8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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