2(2k-4)=4(k-2)

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Solution for 2(2k-4)=4(k-2) equation: 



2(2k-4)=4(k-2)

We move all terms to the left:

2(2k-4)-(4(k-2))=0

We multiply parentheses

4k-(4(k-2))-8=0



We calculate terms in parentheses: -(4(k-2)), so:

4(k-2)

We multiply parentheses

4k-8

Back to the equation:

-(4k-8)



We get rid of parentheses

4k-4k+8-8=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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