2(2l+4)=28

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Solution for 2(2l+4)=28 equation: 



2(2l+4)=28

We move all terms to the left:

2(2l+4)-(28)=0

We multiply parentheses

4l+8-28=0

We add all the numbers together, and all the variables

4l-20=0

We move all terms containing l to the left, all other terms to the right

4l=20

l=20/4

l=5

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