2(2m)+(4m+2)=106

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Solution for 2(2m)+(4m+2)=106 equation: 



2(2m)+(4m+2)=106

We move all terms to the left:

2(2m)+(4m+2)-(106)=0

We get rid of parentheses

22m+4m+2-106=0

We add all the numbers together, and all the variables

26m-104=0

We move all terms containing m to the left, all other terms to the right

26m=104

m=104/26

m=4

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