2(2m)+4(4+2)=108

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Solution for 2(2m)+4(4+2)=108 equation: 



2(2m)+4(4+2)=108

We move all terms to the left:

2(2m)+4(4+2)-(108)=0

determiningTheFunctionDomain
22m-108+4(4+2)=0

We add all the numbers together, and all the variables

22m-108+46=0

We add all the numbers together, and all the variables

22m-62=0

We move all terms containing m to the left, all other terms to the right

22m=62

m=62/22

m=2+9/11

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