2(2m)+4(4m+2)=22m+44m+2=108108

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Solution for 2(2m)+4(4m+2)=22m+44m+2=108108 equation: 



2(2m)+4(4m+2)=22m+44m+2=108108

We move all terms to the left:

2(2m)+4(4m+2)-(22m+44m+2)=0

We add all the numbers together, and all the variables

22m+4(4m+2)-(66m+2)=0

We multiply parentheses

22m+16m-(66m+2)+8=0

We get rid of parentheses

22m+16m-66m-2+8=0

We add all the numbers together, and all the variables

-28m+6=0

We move all terms containing m to the left, all other terms to the right

-28m=-6

m=-6/-28

m=3/14

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