2(2m)+4(m+20)=108

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Solution for 2(2m)+4(m+20)=108 equation: 



2(2m)+4(m+20)=108

We move all terms to the left:

2(2m)+4(m+20)-(108)=0

We multiply parentheses

22m+4m+80-108=0

We add all the numbers together, and all the variables

26m-28=0

We move all terms containing m to the left, all other terms to the right

26m=28

m=28/26

m=1+1/13

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