2(2m+1)+11m=5m+2(4m+7)

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Solution for 2(2m+1)+11m=5m+2(4m+7) equation:



2(2m+1)+11m=5m+2(4m+7)
We move all terms to the left:
2(2m+1)+11m-(5m+2(4m+7))=0
We add all the numbers together, and all the variables
11m+2(2m+1)-(5m+2(4m+7))=0
We multiply parentheses
11m+4m-(5m+2(4m+7))+2=0
We calculate terms in parentheses: -(5m+2(4m+7)), so:
5m+2(4m+7)
We multiply parentheses
5m+8m+14
We add all the numbers together, and all the variables
13m+14
Back to the equation:
-(13m+14)
We add all the numbers together, and all the variables
15m-(13m+14)+2=0
We get rid of parentheses
15m-13m-14+2=0
We add all the numbers together, and all the variables
2m-12=0
We move all terms containing m to the left, all other terms to the right
2m=12
m=12/2
m=6

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