2(2m+1)+11m=5m+2(4m+7)

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Solution for 2(2m+1)+11m=5m+2(4m+7) equation: 



2(2m+1)+11m=5m+2(4m+7)

We move all terms to the left:

2(2m+1)+11m-(5m+2(4m+7))=0

We add all the numbers together, and all the variables

11m+2(2m+1)-(5m+2(4m+7))=0

We multiply parentheses

11m+4m-(5m+2(4m+7))+2=0



We calculate terms in parentheses: -(5m+2(4m+7)), so:

5m+2(4m+7)

We multiply parentheses

5m+8m+14

We add all the numbers together, and all the variables

13m+14

Back to the equation:

-(13m+14)



We add all the numbers together, and all the variables

15m-(13m+14)+2=0

We get rid of parentheses

15m-13m-14+2=0

We add all the numbers together, and all the variables

2m-12=0

We move all terms containing m to the left, all other terms to the right

2m=12

m=12/2

m=6

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